1999 AP Physics C Mech: Conservation of momentum and energy

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The equation (1/2)(mv0)^2 = 1/2(M+m0)gh is invalid for conservation of energy because (1/2)mv0 represents momentum, not energy. The discussion clarifies that the collision between the dart and the block is inelastic, meaning kinetic energy is not conserved, even though momentum is conserved. In the center of mass frame, the total momentum before the collision is zero, but the kinetic energy is non-zero, while after the collision, both the dart and block are at rest, resulting in zero kinetic energy. Therefore, the conservation of energy does not hold in this scenario. Understanding these principles is crucial for solving problems involving collisions in physics.
j04015
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Homework Statement
Check image
Relevant Equations
Conservation of momentum and energy
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Why is (1/2)(mv0)^2 = 1/2(M+m0)gh not a valid equation for conservation of energy?

Isn't the energy from when the dart is shot the same as when the two masses move at speed v?
 
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j04015 said:
Homework Statement: Check image
Relevant Equations: Conservation of momentum and energy

View attachment 336233View attachment 336234
Why is (1/2)mv0 = 1/2(M+m0)gh not a valid equation for conservation of energy?

Isn't the energy from when the dart is shot the same as when the two masses move at speed v?
Your question is whether the collision between the dart and block is elastic or not?
 
To answer the first question,
j04015 said:
Why is (1/2)mv0 = 1/2(M+m0)gh not a valid equation for conservation of energy?
Because ##\frac{1}{2}mv_0## has dimensions of momentum and not energy.
 
kuruman said:
To answer the first question,

Because ##\frac{1}{2}mv_0## has dimensions of momentum and not energy.
Whoops, typo. I meant (1/2)(mv0)^2
 
PeroK said:
Your question is whether the collision between the dart and block is elastic or not?
PeroK said:
Your question is whether the collision between the dart and block is elastic or not?
If the collision wasn't elastic the entire problem doesn't make sense.
 
j04015 said:
If the collision wasn't elastic the entire problem doesn't make sense.
That statement is false!
 
... the collision is manifestly and totally inelastic!
 
PeroK said:
... the collision is manifestly and totally inelastic!
I see the issue now. Momentum is conserved but not energy. Thanks!
 
j04015 said:
I see the issue now. Momentum is conserved but not energy. Thanks!
You can see that if you consider what's going on in the center of mass frame. Before the collision, both dart and block move with opposite momenta. Total momentum is zero and the kinetic energy is non-zero. After the collision, the dart and the block are at rest. Total momentum is zero (conserved) and total kinetic energy is also zero (not conserved).
 
  • #10
kuruman said:
You can see that if you consider what's going on in the center of mass frame. Before the collision, both dart and block move with opposite momenta. Total momentum is zero and the kinetic energy is non-zero. After the collision, the dart and the block are at rest. Total momentum is zero (conserved) and total kinetic energy is also zero (not conserved).
The conservation of energy equations will not be compatible with conservation of energy in any frame if you assume that the dart sticks. However, I agree that considering the com frame makes it very explicit.
 
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