2.3.17 Find the average acceleration for this interval.

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SUMMARY

The average acceleration of an object between time intervals $t=5\, s$ and $t=8\, s$ is calculated using the formula $$a_{av}=\frac{v_2-v_1}{t_2-t_1}$$. Given the initial velocity of $5 \, m/s$ and a final velocity of $-1\, m/s$, the average acceleration is determined to be $-2 \, m/s^2$. While the calculation is confirmed as correct, the discussion raises the question of whether a TikZ graph can be created to represent acceleration, noting that sufficient information is not available to depict the actual curve.

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karush
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2.3.17 At $t=5\, s$ an object is traveling at $5 \, m/s$.
At $t=8\, s$ its velocity is $-1\, m/s$
(a) Find the average acceleration for this interval.
$$a_{av}=\frac{v_2-v_1}{t_2-t_1}=\frac{\Delta v}{\Delta t}$$
So
$$a_{av}=\frac{-1-5}{8-5}=\frac{-6}{3}=-2 \, m/s$$
book answer $-2\, m/s^2$ok I think this is ok
but again was wondering if a tikx graph can be made or is acceleration a curve?
 
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karush said:
2.3.17 At $t=5\, s$ an object is traveling at $5 \, m/s$.
At $t=8\, s$ its velocity is $-1\, m/s$
(a) Find the average acceleration for this interval.
$$a_{av}=\frac{v_2-v_1}{t_2-t_1}=\frac{\Delta v}{\Delta t}$$
So
$$a_{av}=\frac{-1-5}{8-5}=\frac{-6}{3}=-2 \, m/s$$
book answer $-2\, m/s^2$ok I think this is ok
but again was wondering if a tikx graph can be made or is acceleration a curve?
You don't have enough information to draw the actual curve. Just enough to get the average.

-Dan
 

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