- #1

karush

Gold Member

MHB

- 3,269

- 5

A race car strarts from rest and travels east along a straight and level track.

For the firs $5.0s$ of the cars motion,

the eastward compent of the car's velocity,is given by

$v_x(t)=(0.930 m/s^3)t^2 $

What is acceleration of the car when $v_x=14.5$

ok my first step with this was

$$A=\frac{dv}{dt}=1.86t$$

if $v=14.5=0.933t^2$

then

$$t=3.94$$

so

$A(3.94)=1.86\cdot3.94=7.32 m/s^2$

For the firs $5.0s$ of the cars motion,

the eastward compent of the car's velocity,is given by

$v_x(t)=(0.930 m/s^3)t^2 $

What is acceleration of the car when $v_x=14.5$

ok my first step with this was

$$A=\frac{dv}{dt}=1.86t$$

if $v=14.5=0.933t^2$

then

$$t=3.94$$

so

$A(3.94)=1.86\cdot3.94=7.32 m/s^2$

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