2(5) − cot [4 arctan 0.2 + (i/2) ln i] − 1

  • Thread starter Thread starter Jenab2
  • Start date Start date
  • Tags Tags
    Ln
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
10 replies · 2K views
Jenab2
Messages
85
Reaction score
22
Don't ever divide anything by the quantity in the title.

Post your favorite "fancy zeros" here.
 
Mathematics news on Phys.org
axmls said:
$$\frac{1}{12} + \sum _{n = 1} ^\infty n$$

That should probably be

−1/12 + Σ(2,∞) 1/n⁴

Edit: whoops, no. That doesn't seem quite right, either. I evaluated ten million terms of the sum and came up with −0.0010100996222299347, so

−1/12 + 1/999 + Σ(2,∞) 1/n⁴

seems to be nearer to zero.
 
Last edited:
Jenab2 said:
That should probably be

−1/12 + Σ(2,∞) 1/n⁴

Edit: whoops, no. That doesn't seem quite right, either. I evaluated ten million terms of the sum and came up with −0.0010100996222299347, so

−1/12 + 1/999 + Σ(2,∞) 1/n⁴

seems to be nearer to zero.

Nope, it's written as I intended.
 
Unless you specify how divergent sums are to be evaluated, the formula is not well-defined.
Yes there is a specific way that leads to -1/12, but this is by far not the only way to assign finite values to divergent sums.
 
mfb said:
Unless you specify how divergent sums are to be evaluated, the formula is not well-defined.
Yes there is a specific way that leads to -1/12, but this is by far not the only way to assign finite values to divergent sums.

It was a somewhat tongue-in-cheek answer, if that wasn't clear.
 
  • Like
Likes   Reactions: Mentallic
I tried something like this to mess with my maths teacher in senior year once, replaced pi with some weird sums.
 
1 / Σ(1,∞) n = 0
1 / { 1/a + 1 / Σ(1,∞) n } = a, a≠0.
 
## \begin{Vmatrix} \vec\nabla \times \vec\nabla f \end{Vmatrix} ##
 
Last edited:
axmls said:
See here: https://en.m.wikipedia.org/wiki/1_+_2_+_3_+_4_+_⋯
There are ways to assign a value to that sum using alternate methods. That was the "tongue-in-cheek" aspect of my response.
Ah. My difficulty in appreciating the assignment was caused by my thinking of scalars in vector terms. Consider velocities in the same direction, classically being added, tail to head:

v₁ + v₂ + v₃ + v₄ + ...

where each velocity is in the direction of the +x axis and the magnitude of the velocities is proportional to the subscript.

How is it that an object, moving through an infinite succession of changes-of-velocity, all of them forward, might end up moving BACKWARD at a speed of 1/12 velocity units?

I'd figured that this was a case of getting a strange result out of an indeterminate form.