- #1

unscientific

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## Homework Statement

I managed to do part (i) and first part to (ii):

## Homework Equations

U = Q + W

## The Attempt at a Solution

for the**first part**:

T/T

_{f}= 1/(2 - y)

**for (ii)**:

W = yVP

Given: (3/2)R = Q/(nΔT),

Q = (3/2)nR(ΔT)

Therefore U = Q + W

U = (3/2)nR(ΔT) + yVP

But then,

isn't U already equal to (3/2)nR(ΔT) since its a monoatomic gas?

Then that gives y = 0, so I'm utterly confused.Here's what the answer writes:

W = yVP

H = (3/2)nR(T

_{f}- T) (does H here mean U?)

Does this imply that heat transferred Q, equals to zero? so W = U?

But there's no indication that this is an adiabatic process? How can we assume that?