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2 definitions for argument, why?

  1. Feb 17, 2014 #1
    In the wiki, I found this definition for the argument:

    c3b660fcef985a8d0781f6bfb6659a76.png

    http://en.wikipedia.org/wiki/List_of_trigonometric_identities#Exponential_definitions

    However, in other page of the wiki (http://en.wikipedia.org/wiki/Complex_conjugate#Use_as_a_variable), I found this definition for argument:[tex]\arg(z) = \ln(\sqrt[2 i]{z \div \bar{z} }) = \frac{ln(z) - ln(\bar{z})}{2 i}[/tex]I don't understand why exist 2 defitions for the argument and how those 2 defitions are related.
     
  2. jcsd
  3. Feb 17, 2014 #2

    pasmith

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    Homework Helper

    This gives the inverse of [itex]\mathrm{cis}\,\theta = \cos \theta + i \sin \theta = e^{i\theta}[/itex]. It is not a definition of the argument, but reflects the fact that if [itex]z = e^{i\theta}[/itex] then
    [tex]
    -i \log e^{i\theta} = -i(i \theta) = \theta = \arg z.
    [/tex]
    It doesn't give [itex]\arg z[/itex] if [itex]|z| = R \neq 1[/itex]:
    [tex]
    -i \log (Re^{i\theta}) = -i \log R + \theta \neq \arg z
    [/tex]

    This gives [itex]\arg z[/itex] for any [itex]z \neq 0[/itex] (if you choose the correct branch of [itex]z^{1/(2i)}[/itex]).
     
  4. Feb 17, 2014 #3
    I liked your answer!
     
  5. Feb 17, 2014 #4

    Chronos

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    Science Advisor
    Gold Member

    There is almost always an alternative way of expressing the same mathematical argument, with a little imagination. It's not always obvious.
     
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