1. The problem statement, all variables and given/known data A rocket is initially at rest on the ground. At time = 0, its engines ignite causing the rocket to move in a straight line with constant total acceleration of a = 30 m/s^2 at an angle of 76 degrees, and the engines are strong enough to counter gravity and keep it exactly in a straight line. The rocket stays in a straight line with increasing speed for 15 seconds until the engines fail and the rocket goes into free fall. In this problem, the acceleration of gravity is approximated to g= 10 m/s^2. X-direction is the ground and Y-direction is along the upward direction a) Find the position and velocity vectors of the rocket right before the engines fail. 2. Relevant equations ΔX = Vit + .5(a)(t)^2 V = at 3. The attempt at a solution When I tried to solve it, I split up the Acceleration into two components, the x and the y. Ax = 30cos(76) = 7.26 m/s^2 and Ay = 30sin(76) = 29.11 m/s^2 Then, I plugged the acceleration components into the V= at formula respectively. So Vx = (7.26)(15) = 108.9 m/s and Vy = (29.11)(15) = 436.65 Now that I found the velocity vectors, I proceeded to find the position vectors. ΔX = (0)(15) + .5(7.26)(15)^2 = 816.75 m. I set Vi as 0 because it started at rest. ΔY = (0)(15) + .5(29.11)(15)^2 = 3274.88 m. Same thing with the above. I have doubts on my answer, because the values look too huge. So I think I did something wrong in terms of either formula usage, or splitting up the acceleration into components or both.