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- How can explain the difference of these red dots?
- Red line = Green line ?. How to explain it?

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- Thread starter Supitha
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In summary, the difference between the red and green lines in the first figure is due to the "work function" of the metal, which determines the likelihood of electrons escaping when exposed to different frequencies of light. The second figure shows two different intensities at the same wavelength, with the "stopping potential" remaining the same due to the same photon energy. However, the more intense light results in more electrons being liberated per second. In all curves, increasing the applied voltage will not significantly affect the number of electrons being pulled, leading to a saturation point.

- #1

- 4

- 2

- How can explain the difference of these red dots?
- Red line = Green line ?. How to explain it?

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So at low photon frequencies, there is a smaller chance that an electron will end up with enough energy to leave the metal (because total energy = photon energy + random thermal energy). For high photon energies, there is more chance of escaping i.e. more chance that electron's original thermal energy plus photon energy will carry it over the work function threshold.

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Thank you so much.Swamp Thing said:

So at low photon frequencies, there is a smaller chance that an electron will end up with enough energy to leave the metal (because total energy = photon energy + random thermal energy). For high photon energies, there is more chance of escaping i.e. more chance that electron's original thermal energy plus photon energy will carry it over the work function threshold.

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What's happenning in second one?

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No. The second picKizer said:who me?

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Going back to fig. 1, all curves involve the same intensity (same rate of photons per second) so they all saturate at the same number of electrons per second. If you increase the applied voltage to a huge value, you can still pull only those electrons that are liberated by photons, so "pulling harder" won't make much difference -- so the curves saturate at some point.

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