- #1

TrpnBils

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## Homework Statement

A 50m zipline is hung 11m off of the ground at its starting point (assume it ends at ground level). If you are to drop an object which is 20m along the ground from the start of the zipline, how far down the line would you need to let it go?

## Homework Equations

d=((V

_{F}+V

_{I})/2)*t

V

_{F}= V

_{I}+ a*t

D=(V

_{F}*t) + 0.5*a*t

^{2}

V

_{f}

^{2}= V

_{I}

^{2}+ 2*a*d

## The Attempt at a Solution

I was able calculate the time as 25s for the entire line, which gives an acceleration of 16m/s/s and a final velocity of 40m/s. Also solved for:

- Vfx (max) = 39.2m/s
- Vfy (max) = 8.8m/s
- ax = 15.7m/s/s
- ay = 3.52 m/s/s

What equation do I use to calculate the release point along the zip line? This stuff is easy if the plane of motion is parallel to the ground, but in this case it's a decreasing distance at an angle...