2D Kinematics Please Help! I tried so hard Relative to the ground, a car has a velocity of 17.3 m/s, directed due north. Relative to this car, a truck has a velocity of 20.5 m/s directed 48.5 ° south of east. Find the (a) magnitude and (b) direction of the truck's velocity relative to the ground. Give the directional angle relative to due east. I got: Vcg = 0x + 17.3y Vtg = 20.5 cos (45) - 20.5 sin(45) The resultant is: 14.496x + 2.804y So, by the Pythagorean theorem, Vtg = 14.765 (But that's wrong) And the direction would be: Inverse tangent of (2.804/14.496) so it's 10.948 degrees And that's wrong too. I also tried it with adding the 20.5 sin(45) on the Vtg part, but those answers are wrong too. I dont know what to do!