2D Kinematics Problem (Projectile Motion)

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The discussion revolves around a physics problem involving projectile motion, specifically calculating the angle at which a cannonball must be fired to hit a target 402.3 meters away with an initial velocity of 67 m/s. The participant is struggling to find the necessary equations to relate horizontal and vertical motion, noting that they lack sufficient information to solve for unknown variables. They are advised to express the horizontal distance in terms of time and the angle of projection, as well as to consider the vertical displacement, which should be zero since the terrain is level. Key components of the solution involve using the x and y components of the initial velocity, V0 cos(theta) and V0 sin(theta), respectively. The conversation emphasizes the need for a systematic approach to resolve the problem using the relevant kinematic equations.
Dcarroll
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Homework Statement


Hi, I'm in a calculus base physics course in college so i thought this forum would be appropriate to post this question. The question is as follows:

"A cannonball leaves the end of the cannon with an initial velocity of 67 m/s. Assuming a level terrain, at what angle(s) to the horizontal must the cannonball be fired to hit a target 402.3 meters away?"


Homework Equations


X=Xo+Vo(t)+(1/2)(a)(t)^2
V=Vo+a(t)
V^2=Vo^2+(2)(a)(X2-X1)


The Attempt at a Solution


Basically i have been struggling with this problem for awhile now and I'm stuck. I wrote out my horizontal and vertical information in an attempt to maybe find the time it takes for the object to reach its target. It turns out there is not enough information to solve for any of the un-known variables in the equations I listed above. I also cannot use SOH-CAH-TOA to solve for the vertical and horizontal velocities because they don't give enough information.

If anyone can help me through the steps on how to solve this it would be great!
 
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Call the angle of projection theta, \theta.

In terms of theta, write an equation relating the horizontal distance traveled with the time of flight. You will have two unknowns, theta and the time of flight.

Again in terms of theta, write an equation for vertical displacement from the start of the motion to the end (net vertical displacement should be zero since the ground is level). Again, you will have two unknown variables, the angle of projection and the time of flight.
 
Dcarroll said:

Homework Statement


Hi, I'm in a calculus base physics course in college so i thought this forum would be appropriate to post this question. The question is as follows:

"A cannonball leaves the end of the cannon with an initial velocity of 67 m/s. Assuming a level terrain, at what angle(s) to the horizontal must the cannonball be fired to hit a target 402.3 meters away?"


Homework Equations


X=Xo+Vo(t)+(1/2)(a)(t)^2
V=Vo+a(t)
V^2=Vo^2+(2)(a)(X2-X1)
X is important, of course, but the last two equations are not relevant. What is relevant, that you have NOT given is the y component. What are the equations for vertical motion?

Also, you need the fact that the x component of initial velocity is V0 cos(theta) and the y component is V0 sin(theta).


The Attempt at a Solution


Basically i have been struggling with this problem for awhile now and I'm stuck. I wrote out my horizontal and vertical information in an attempt to maybe find the time it takes for the object to reach its target. It turns out there is not enough information to solve for any of the un-known variables in the equations I listed above. I also cannot use SOH-CAH-TOA to solve for the vertical and horizontal velocities because they don't give enough information.

If anyone can help me through the steps on how to solve this it would be great!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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