- #1

Kyros

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## Homework Statement

A baseball is hit into the air, nearly vertically, with a speed of 27 m/s. When it comes down, the ballplayer catches it in his glove. Air resistance (drag) is actually fairly important for a baseball in flight, but for now let’s assume it is negligible.(a) How high does the baseball go, and how long is it in the air?

(b) As the player catches the ball, his glove moves downward by 12 cm before coming to rest. Based on this, estimate the acceleration of the ball as it is caught.

**Variables:**

V=27 m/s

Acceleration= g= 9.8

Vo= 0 m/s

Xo=0 m

x=?

t=?

## Homework Equations

kinematic equations for constant acceleration:

V=Vo+at

X=X0+V0t+1/2at^2

V^2=Vo^2+2a(X-Xo)

Average V= (V+Vo)/2

v= change in x/ change in t

a= change in v/change in t

## The Attempt at a Solution

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a.

V= Vo+(at)

27= (0)+ 9.8t

t= 2.76 seconds

X=Xo+Vot+1/2at^2

x=(0)+(0)(2.76)+1/2(9.8)(2.76)^2

x=37.32m

b.

this is where i get lost...

12cm= .12m

x= 37.32 +.12m = 37.44m

t= 2.76 seconds

v= 37.44 /2.76 = 13.57m/s

a= 13.57m/s/2.76

a= 4.92Thats my attempt, I'm really lost so any advice or help will be appreciated. I'm not too confident about my answer but a too. Also, is b just 9.8? since its just gravity acting on the ball.

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