2nd fundamental theorem of calculus

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The discussion centers on the confusion surrounding the Second Fundamental Theorem of Calculus (FTC), particularly its terminology and application in different textbooks. The second FTC is identified as the Integral Evaluation Theorem, which states that the definite integral of a function from a to b can be evaluated using its anti-derivative. Participants clarify that while some textbooks may label theorems differently, the core concepts remain consistent. The conversation also touches on the need for understanding both the proofs and practical applications of these theorems in solving problems. Overall, the thread emphasizes the importance of grasping the fundamental ideas behind the theorems rather than just memorizing their statements.
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Can some on pleases explain this too me. I have an AP book, and i am to do a few problems out of it for class, and but can't find it in there ANY WHERE. Any help would be superb!
-Jacob
 
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Finney's book has this backwards... The second F of C is the Integral Evaluation Theorem... Which is the mathworld's 1st...

Its hand stuff!
 
I've seen it both ways in several books. Luckily, no teacher has ever asked me to state FTC #1 or state FTC #2, they've only asked me to be able to use them.
Did you try any of the problems yet?
 
Do you need to understand the proofs? Or just understand the idea?

FTC#2 says
\int^b_a f(x)dx = F(b) - F(a)

where the anti-derivative of f(x) is F(x)

So what you are probably using this Thrm for is evaluating definite integrals (ones with A and B stated).

So what you do is find the anti-derivative of f(x) i.e. F(x), and then evaluate that anti-derivative at a and b, then take the absolute value of their difference.

For example if we wanted to evaluate:

\int^5_1 3x^2dx

we would first find the anti derivative of 3x^2.

Which is x^3.

Then we would evaluate x^3 at 1 and 5 which gives us, 1 and 125. We subtract 1 from 125 and get 124, hence:

\int^5_1 3x^2dx = 124
 
thanx you guys. I know how to do those with my eyes closed, its just that my AP book has a real habit of doing things w/o thouroughly explaining them. thanks again ill tell my friends about this site!
-Jacob
 
2nd FTC: If f is any riemann integrable function on the closed bounded interval [a,b], and G is a Lipschitz - continuous function such that for every point x where f is continuous, G is diiferentiable at x with G'(x) = f(x), then the integral of f from a to b, equals G(b)-G(a).

Recall that G is lipschitz continuous on [a,b] if there exists a constant K such that for all points u,v in [a,b] we have |G(v) - G(u)| <= K|v-u|.
 
Is the first theorem just:

y=x^n
dy/dx=nx^n-1

Is that it?

I wrote general proof for the derivative of a function x^n. Using limits of course, and I ended with nx^n-1, which is what you are suppose to get.

I never seen the proof yet, and it would be great to do it independently.

So, what is the 1st Fundamental Theorem(in most books)?
 
in most books it says that if f is continuous on [a,b] and G(x) is the integral of f from a to x, then G is differentiable on [a,b] and G'(x) = f(x) for every x in [a,b].

The more general statement is that if f is a Riemann integrable function on [a,b] and G(x) again is the injtegral of f from a to x, then G is Lipschitz continuous, and G is differentiable with G'(x) = f(x) at those points where f is continuous.

Then to derive the 2nd thm from the first you need the generalized mean value theorem, that a function G which is lipschitz continuous and has derivative equal to zero almost everywhere (i.e. except on a set of measure zero) is constant.

in most books the 2nd thm just says that if f is continuous on [a,b] and G is continuous on [a,b] with G'(x) = f(x) for all x in (a,b), then the integral of f from a to b, equals G(b)-G(a).
 
Last edited:
  • #10
The Riemann Sum?

You can find the value under a curse with it.
 

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