2nd order DEQ: weird solution method

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Homework Help Overview

The discussion revolves around finding a second solution to a second-order differential equation of the form y'' + p(t)y' + q(t)y = 0, given that one solution is y(t) = e^(2t). Participants explore the method of variation of parameters and its application to derive a first-order linear differential equation for an unknown function m(t) related to the second solution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivation of m'(t) and the application of variation of parameters. Some express uncertainty about the technique and seek suggestions for starting points. Others question the appropriateness of the method given the nature of the differential equation.

Discussion Status

The conversation includes various suggestions and approaches, with some participants indicating that they have found helpful guidance. There is acknowledgment of the complexity involved in the methods discussed, and at least one participant expresses confidence in having derived m'(t) successfully.

Contextual Notes

There is mention of constraints related to the method of variation of parameters being typically used for homogeneous equations, and a participant notes the potential for confusion in applying different methods. Additionally, some participants reflect on the challenges of solving these equations by hand.

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Homework Statement



Suppose that u(t) is a solution to

y'' + p(t)y' + q(t)y = 0

Suppose a second solution has the form

y(t) = m(t)u(t)

where m(t) is an unknown function of t. Derive a first order linear differential equation for m'(t).

Suppose y(t) = e^(2t). Use the method above to find a second solution to this equation.

The Attempt at a Solution



I tried:

y = m*u
=> m = y/u
=> m' = (y'/u) - (y/(u^2))*u'

There isn't anything in my book or in my class notes that describes the technique to be used here. Does anyone have any suggestions on how to get started?
 
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Surely this is recommended where e^{2t} is a solution to the original 2nd order diff. eq. Right? Then, like Mindscrape says, it's variation of parameters.
 
try using this equation:

Y2=y1*integral{[e^(-integral p(t))dt]}/[(y1)^2]dt

y1=y(t)=e^(2t)

then the general solution is: y=c1y1+c2y2
 
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And also to add, your method works best when the p(t)y' value is excluded from the equation. You can solve your problem by the method you mentioned above, but it cost much time and leaves much room for mistakes, and you are essentially guessing by trial and error by multiplying u(t) by respective powers of x, or m, as you would put it. So therefore, for the sake of your precious time and of doing unneeded amount of work, you should try this equation. Tell me how it works, I believe you will learn to like it. And, later you will learn to solve these problems without the guesswork, but the problems get very tedious, believe me... I'm not a big fan of solving these equations by hand.
 
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this is an inhomogeneous differential equation. the method of variation of parameters is for homogeneous. in the wikipedia article it is said to "determine the homogeneous solution using a method of your choice"

as for as the other method is concerned: how can I use this method to derive a general first order linear differential equaiton for m'(t)? by the way mathgician, this method works great for finding the second solution!
 
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never mind, mathgician, i out the way to find m'(t). your input helped a lot. i will post my solution to the problem if anyone is interested.
 

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