3 body relativistic phase space

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SUMMARY

The discussion centers on the integrated 3-body relativistic phase space for three particles of equal mass, specifically in the context of K+ decay to pi+ pi+ pi-. The formula provided for the integrated phase space is Φ = (1/(π³ 2⁷ M²)) ∫(s₂ to s₃) [(1/s) √((s-s₁)(s-s₂)(s₃-s)(s₄-s))] ds, where M is the initial mass and s₁, s₂, s₃, and s₄ are defined in terms of the particle masses. The user expresses difficulty in performing the integral analytically and suggests numerical integration as a viable approach. Additionally, a request for a similar formula for the integrated four-body phase space is made.

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Final
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Hi,
Do you know if there is an explicit formula for the integrated 3 body relativistic phase space of 3 particle with the same mass? I.e. M->3m
Or an approximate one?
Thank you!
 
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There is only the differential cross section... I need the total cross section i.e. the integral of your formula. In the case of 3 massive body I think I can't integrate it. I did only the numerical integration...
 
In the case of a K+ --> pi+ pi+ pi-, I think the total probability of the decay is the probability of decaying between point 1 and point 2, times the branching ratio for this decay mode (~21.5%).
 
I didn't understand what is point 1 and point 2...
Anyhow I found the formula for the integrated 3 body phase space:
\Phi= \frac{1}{\pi^3 2^7 M^2} \int_{s_2}^{s_3}{\frac{d s}{s} \sqrt{(s-s_1)(s-s_2)(s_3-s)(s_4-s)}},<br />
Where M is the mass of the initial state and s_1=(m_1-m_2)^2, \quad s_2=(m_1+m_2)^2, \quad s_3=(M-m_3)^2, \quad s_1=(M+m_3)^2<br />.
I think you can do this integral only numerical...
 
http://www.google.com"
 
Last edited by a moderator:
thanks a lot! ...
 
Help! Four body relativistic phase space

Hello everybody!

I urgently need the value of the integrated four body phase space, whereby the four outgoing particles all have equal mass m.
So I need the analogon of the formula for Phi which "Final" posted, but this time for four outgoing particles...

Thanks a lot,

Basti
 

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