3 Photons going through 3 Polarizers

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SUMMARY

The discussion focuses on the probability of vertically polarized photons passing through a sequence of three polarizers set at 45 degrees, 75 degrees, and 45 degrees. The initial probability of a photon passing through the first polarizer is 50%, with subsequent probabilities calculated using the formula Probability = cos²(θ). The challenge lies in determining the correct angle θ for the second polarizer (75 degrees) to continue the calculations for the final outcome of the photons.

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  • Basic probability theory as it applies to quantum mechanics
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Homework Statement


Suppose we set up a sequence of three polarizers with orientations 45 degrees, 75 degrees and 45 degrees, where the angles refer to how much each polarizer is rotated relative to the vertical direction.

If we send three vertically (i.e. 0 degrees) polarized photons in either 0, 1, 2, or 3 photons might pass through all the polarizers. What is the probability for each of these possibilities?

Homework Equations



lθ> = cos(θ)l0 degrees> + sin(θ)l90 degrees> (Dirac Notation)
Probability = cos^2(θ)

The Attempt at a Solution



Well what I have is that when the photons go through the first polarizer, the probability of 1 getting through is 50%, 25% for 2 and so on. Then the photons become polarized at 45 degrees. I'm just having a hard time figuring out how to continue through the 75 degrees polarizer and the last 45 degree polarizer. All I want to know is how to set up the photons going through the 75 degree polarizer, from there I can get the rest.
 
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When you say the probability is equal to ##\cos^2 \theta##, what exactly does ##\theta## represent? If you understand that, how to deal with the second polarizer is straightforward.
 

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