3D geometry: parametric equation and tangents

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SUMMARY

The discussion centers on the interpretation of the parametric equation defined by the functions x=t, y=t², and z=t³, represented as the vector equation \(\vec{r}=t\hat{i}+t^2\hat{j}+t^3\hat{k}\). This vector describes a curve in three-dimensional space, where each value of the parameter t corresponds to a point on the curve. The derivative \(\frac{dr}{dt}\) indeed provides the tangent vector to the curve at any given point, confirming its role in understanding the curve's direction and slope.

PREREQUISITES
  • Understanding of parametric equations in three dimensions
  • Knowledge of vector notation and operations
  • Familiarity with calculus concepts, specifically derivatives
  • Basic skills in plotting points in a 3D coordinate system
NEXT STEPS
  • Explore the visualization of 3D curves using graphing software like GeoGebra
  • Study the concept of tangent vectors in multivariable calculus
  • Learn about the applications of parametric equations in physics and engineering
  • Investigate the relationship between parametric equations and vector fields
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Students and professionals in mathematics, physics, and engineering who are working with 3D geometry and need to understand parametric equations and their derivatives.

AdityaDev
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I have a doubt in 3d geometry. I calculus and I know how to do partial derivatives.(but I don't know what it means).
If you have a parametric equation ##x=t, y=t^2,z=t^3## (the equation is randomn)
What does ##\vec{r}=t\hat{i}+t^2\hat{j}+t^3\hat{k}## represent?
now if it represents the position vector or the vector connecting origin and a point on the curve, then will ##\frac{dr}{dt}## give the tangent to the curve?
 
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AdityaDev said:
I have a doubt in 3d geometry. I calculus and I know how to do partial derivatives.(but I don't know what it means).
If you have a parametric equation ##x=t, y=t^2,z=t^3## (the equation is randomn)
What does ##\vec{r}=t\hat{i}+t^2\hat{j}+t^3\hat{k}## represent?
It represents a curve in three-dimensional space. For each value of the parameter t, you get a vector from the origin to a point on the curve. To see what this curve looks like, plot 8 or 10 points and connect them.
AdityaDev said:
now if it represents the position vector or the vector connecting origin and a point on the curve, then will ##\frac{dr}{dt}## give the tangent to the curve?
Yes
 
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