3x^2 - 5x - 1 = 0 (Solve using completing the square method)

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Homework Help Overview

The problem involves solving the quadratic equation 3x² - 5x - 1 = 0 using the completing the square method. Participants are discussing the steps taken to manipulate the equation and the validity of those steps.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to complete the square but faces scrutiny regarding a specific step in their manipulation of the equation. Participants question the transition from one equation form to another, highlighting a potential misunderstanding of algebraic principles.

Discussion Status

Some participants provide feedback on the original poster's work, suggesting corrections to the algebraic steps. There is a collaborative effort to clarify the reasoning behind the transformations made in the equation.

Contextual Notes

Participants note that the original poster expressed uncertainty about their working and requested verification of their answer. There are indications of edits made to clarify the steps involved in the completing the square process.

Mphisto
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Homework Statement


Question: 3x^2 - 5x - 1 = 0 (Solve using completing the square method)


Homework Equations





The Attempt at a Solution


3x^2 - 5x - 1 = 0
x^2 - (5/3)x - 1/3 = 0
x^2 - (5x/3) = 1/3
x^2 - 2(5x/3) = 1/3
x^2 - 2(5x/3) + (5/6)^2 = 1/3 + (5/6)^2
(x - 5/6)^2 = 1/3 + 25/36
(x - 5/6)^2 = 37/36
x - 5/6 = + - Square root 37/36
x = Square root 37/36 + 5/6 or x = - Square root 37/36 + 5/6
x = 1.85 (3sf) or x = -0.180 (3sf)

I am sorry if the working is messy! I can't find the appropriate key for it
Please check my answer and correct me

Thank you!
 
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Mphisto said:
x^2 - (5x/3) = 1/3
x^2 - 2(5x/3) = 1/3
How did you get from the first to the second? What you basically said here is that if

a+b=c

then

a+2b=c

This is not true unless b=0, which is not the case. What you should have instead done is

a+b=c

then

a+2(\frac{b}{2})=c

Notice here that nothing has changed, so the equality still holds.

Everything else seems good and you have the correct answer :smile:
 
Mentallic said:
How did you get from the first to the second? What you basically said here is that if

a+b=c

then

a+2b=c

This is not true unless b=0, which is not the case. What you should have instead done is

a+b=c

then

a+2(\frac{b}{2})=c

Notice here that nothing has changed, so the equality still holds.

Everything else seems good and you have the correct answer :smile:
Thanks for taking the time to check!

Edit: It should has been x^2 - 2(5x/6) = 1/3
x^2 - 2(5x/6) + (5/6)^2 = 1/3 + (5/6)^2
 
Mphisto said:
Thanks for taking the time to check!

Edit: It should has been x^2 - 2(5x/6) = 1/3
x^2 - 2(5x/6) + (5/6)^2 = 1/3 + (5/6)^2

Yep that's better!
 

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