4.2.5 AP Calculus Exam int of e

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Discussion Overview

The discussion revolves around the evaluation of the integral $\displaystyle2 \int _1^2 e^u \, du$ and the implications of changing variables from \( x \) to \( u \) in the context of a calculus problem. Participants explore the effects of this change on the limits of integration.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant notes that their calculator returned the expression $\displaystyle2 \int _1^2 e^u \, du$ but expresses uncertainty about the reasoning behind it.
  • Another participant provides a substitution \( u=\sqrt{x} \) and derives the transformed integral, stating that it leads to the expression \( 2 \int_1^2 e^u \, du \).
  • A participant questions why the limits of integration change when substituting variables, seeking clarification on the process.
  • One response clarifies that changing the variable from \( x \) to \( u \) necessitates changing the limits of integration, explaining that the original integral over \( x \) from 1 to 4 translates to \( u \) limits from 1 to 2.
  • Another participant reiterates that when changing from \( x \) to \( u \), all references to \( x \) must be converted to \( u \), detailing how the limits correspond to the values of \( u \) derived from \( x \).

Areas of Agreement / Disagreement

Participants generally agree on the necessity of changing the limits of integration when substituting variables, but there is some uncertainty expressed regarding the initial reasoning behind the calculator's output.

Contextual Notes

The discussion does not resolve the initial uncertainty about the calculator's output, and there may be assumptions regarding the understanding of variable substitution that are not explicitly stated.

karush
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View attachment 9321

calculator returned this but know sure why
$\displaystyle2 \int _1^2e^udu$
note there might be a duplicat of this post ?
 

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$u=\sqrt{x} \implies du = \dfrac{1}{2\sqrt{x}} \, dx$

$${\color{red}{2}} \int_1^4 \frac{e^{\sqrt{x}}}{{\color{red}{2}} \sqrt{x}} \, dx = 2 \int_1^2 e^u \, du$$
 
skeeter said:
$u=\sqrt{x} \implies du = \dfrac{1}{2\sqrt{x}} \, dx$

$${\color{red}{2}} \int_1^4 \frac{e^{\sqrt{x}}}{{\color{red}{2}} \sqrt{x}} \, dx = 2 \int_1^2 e^u \, du$$

Why would that change the limits,?
 
karush said:
Why would that change the limits,?
The original integral over x was done over an interval (1, 4).

When we changed the variable to u(x) we are no longer integrating over x. We are now integrating over u. So the interval changes to (1, 2).

-Dan
 
When you change from x to u, every reference to "x" has to change to a reference to "u". "\int_1^4 dx" means we are taking the integral fron x= 1 to x= 4. We have to change that to u. When x= 1, u= \sqrt{1}= 1 and when x= 4, u= \sqrt{4}= 2.
 

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