4th Vertex in a 3D Parallelogram

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SUMMARY

The discussion centers on finding the fourth vertex S of a 3D parallelogram defined by vertices P (2, 0, -1), Q (-2, 4, 1), and R (3, -1, 0). The equations used are PR = QS and PQ = RS. The calculated result for S is (-1, 3, 2), which multiple participants confirm as correct despite initial doubts about the problem statement's clarity regarding adjacent sides.

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Temp0
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Homework Statement


Let P, Q, and R be the vertices of a parallelogram with adjacent sides PQ and PR. Find the other vector S.
P (2, 0 ,-1), Q (-2, 4, 1), R (3, -1, 0)


Homework Equations


PR = QS
PQ = RS


The Attempt at a Solution


I took the two equations and solved both of them, getting (-1, 3, 2) for S by making the coordinates of S into x, y, and z and solving the equations. However, my answer doesn't seem to be correct. Why am I wrong? Thank you in advance.
 
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Hi Temp0! :smile:
Temp0 said:
Let P, Q, and R be the vertices of a parallelogram with adjacent sides PQ and PR. Find the other vector S.
P (2, 0 ,-1), Q (-2, 4, 1), R (3, -1, 0)

I took the two equations and solved both of them, getting (-1, 3, 2) for S

I don't understand your method, but your result seems correct. :confused:

(are you sure it isn't "with adjacent sides PQ and QR"?)
 
yeah... I get S = (-1,3,2) also.
 
tiny-tim said:
Hi Temp0! :smile:


I don't understand your method, but your result seems correct. :confused:

(are you sure it isn't "with adjacent sides PQ and QR"?)

Just checked, nope, PQ and PR... I think it might be a mistake in the book ;_;
 

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