A 1.2 kg block is pushed under water and held there. What is the buoyant force?

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SUMMARY

The buoyant force acting on a 1.2 kg block submerged in water is calculated to be 11.76 N. This value is derived using the formula for weight (w = mg), where the mass (m) is 1.2 kg and the acceleration due to gravity (g) is 9.8 m/s². The discussion clarifies that the buoyant force equals the weight of the water displaced by the block, confirming that if the buoyant force equaled the block's weight, it would float rather than require external force to remain submerged.

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A 1.2 kg block is pushed beneath the water and held there. What is the buoyant force
(in N) acting on the block?
(a) not enough information to answer
(b) 11.76
(c) 1.2
(d) 14.56
(e) none of these

Since buoyant force is equal to the wt of the water displaced, I used the equation w=mg
w=1.2 x (9.8)
so I got 11.76 as my answer.
Is this right?
 
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If the buoyant force were equal to the weight, mg, it would not be necessary to push the block under water- it would float at whatever depth you placed it. The buoyant force is equal to weight of water displaced. The buoyant force is, as you say, the weight of the water displaced- and that will be equal to the density of water times the volume of the block.
 
Thank you! It makes sense now
 

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