A 300 kg rocket sits on a launch pad. What is the thrust nee

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Homework Help Overview

The discussion revolves around calculating the thrust needed for a 300 kg rocket to achieve a thrust to weight ratio of 3:1. Participants explore the relationship between thrust and weight, as well as the implications of the thrust to weight ratio in the context of rocket physics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of thrust to weight ratio and its significance. There are attempts to clarify the formula for calculating thrust and weight, with some questioning how to derive the necessary thrust from the given weight.

Discussion Status

The discussion is active, with participants providing insights into the thrust to weight ratio and engaging in calculations. Some have offered guidance on how to approach the problem, while others express uncertainty about the steps needed to find the thrust.

Contextual Notes

Participants note the weight of the rocket as calculated from its mass and the acceleration due to gravity. There is a focus on understanding ratios and the implications of achieving a specific thrust to weight ratio.

j doe
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Homework Statement


A 300 kg rocket sits on a launch pad. What is the thrust needed to obtain a thrust to weight ratio 3:1?

Homework Equations



The Attempt at a Solution


300.0 kg x 9.817 m/s2 = 2945.1 N

i know this is not the correct answer, but i have no idea where to start. can someone please help?
 
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Hello JD,
what do you think they mean with a thrust to weight ratio ?
 
the amount of acceleration it needs in order to thrust an object with the mass of 300 kg?
 
I do not have much experience with this sort of equation but I believe that the equation for thrust to weight ratio is T/W where T is the force of the thrust and W is the weight of the given body measured in Newtons hope this helps
 
Kaura said:
I do not have much experience with this sort of equation but I believe that the equation for thrust to weight ratio is T/W where T is the force of the thrust and W is the weight of the given body measured in Newtons hope this helps

so based on your equation, would it be 3 / 2945.1 N? that would equal 0.00101864113. what would the units be?
 
j doe said:
so based on your equation, would it be 3 / 2945.1 N? that would equal 0.00101864113. what would the units be?

I think you would have to find the force of thrust so that T/W would be equivalent to 3/1
 
Kaura said:
I think you would have to find the force of thrust so that T/W would be equivalent to 3/1
how do i do that?
 
j doe said:
how do i do that?
Do you know what a ratio is?

Here's an example:

The ratio of centimeters to meters is 100 to 1.

You are asked to find the thrust such that a thrust to weight ratio of 3 to 1 is obtained. You have already determined the weight of the rocket.
 
SteamKing said:
Do you know what a ratio is?

Here's an example:

The ratio of centimeters to meters is 100 to 1.

You are asked to find the thrust such that a thrust to weight ratio of 3 to 1 is obtained. You have already determined the weight of the rocket.
do i multiply 2945.1 by 3? I'm not quite sure how to find the thrust.
 
  • #10
j doe said:
do i multiply 2945.1 by 3? I'm not quite sure how to find the thrust.
weight = mass × acceleration due to gravity

You calculated the weight of the rocket in Post #1 (2945.1 N)

You want the thrust o this rocket to be 3 times its weight.

Therefore, the thrust = ?
 
  • #11
SteamKing said:
weight = mass × acceleration due to gravity

You calculated the weight of the rocket in Post #1 (2945.1 N)

You want the thrust o this rocket to be 3 times its weight.

Therefore, the thrust = ?
thrust = 2945.1 N x 3 = 8835.3 N?
 
  • #12
j doe said:
thrust = 2945.1 N x 3 = 8835.3 N?

I believe that that is correct

If this is the case then excellent job
 
  • #13
j doe said:
thrust = 2945.1 N x 3 = 8835.3 N?
That looks OK.
 

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