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A ball launched on a imclined plane

  1. Oct 12, 2010 #1
    1. The problem statement, all variables and given/known data
    The cart is rolling down an inclined plane which is at an angle  to the horizontal.
    When the cart’s speed is V, the ball is launched. When the ball returns to the same initial perpendicular distance above the track, does it land in the funnel, to the right of the funnel, or to the left of the funnel?


    2. Relevant equations
    yf = yi + Viy*t + 1/2ay*t^2
    xf = xf + Vix*t + 1/2ax*t^2

    3. The attempt at a solution
    I was thinking then the Xball would be something like
    Xf ball = Vix(ball)*t + V(launch x) * t
    Xf car = Vix(car)*t + 1/2(gx)t^2
    Vix ball / car are equal...so in this case i have to determine whether V(launch x) * t is larger or 1/2(gx)t^2 is larger...there were no numbers given so i and very confused right now thinking maybe my attempt is on the wrong track, can someone help me?
     
  2. jcsd
  3. Oct 13, 2010 #2
    Is the ball launched perpendicular to the ground(x axis) or to the cart(inclined plane)?
     
  4. Oct 14, 2010 #3
    perpendicular to the cart
     
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