1. The problem statement, all variables and given/known data A car moves on a straight road. Initially the velocity is 0. Then, for 5.1 seconds the car has constant acceleration a1. Then for 4.2 seconds the car has constant acceleration a2. At the end of the second period of acceleration the car is again at rest. The final position is 41.5 meters from the inital position. Setermine a1 and a2. 2. Relevant equations x(t) = xo +vo*t + .5a(t^2) v(t) = vo*t +at 3. The attempt at a solution I have been trying to use both of these equations and their derivatives to find a1 and a2. I have tried calculating x1 = .5a(t^2) and x2 = x1f + v1 + .5(a2)(t^2). Then I take these and do x1+x2=41.5m. however, I have not been able to get just a1 or a2.