A conducting wire has a resistivity

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SUMMARY

A conducting wire's resistivity, denoted as ρ, is directly proportional to its length L, expressed as ρ = (ρ0)(L), where ρ0 is a constant. The resistance R of the wire can be calculated using the formula R = (ρL)/A, leading to the conclusion that the correct expression for resistance is R = [(ρ0)(L)]/A. The other options presented in the discussion do not accurately represent the relationship between resistivity, length, and cross-sectional area.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the concept of resistivity in materials
  • Knowledge of the formula for resistance R = (ρL)/A
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the relationship between resistivity and temperature in conductors
  • Learn about the impact of cross-sectional area on resistance
  • Explore the derivation of resistance formulas in different geometries
  • Investigate the effects of material properties on electrical conductivity
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Students studying physics or electrical engineering, educators teaching concepts of resistivity and resistance, and anyone looking to deepen their understanding of electrical properties in conductive materials.

Jay9313
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Homework Statement



A conducting wire has a resistivity, ρ as a function of its length, L, given by ρ=(ρ0)(L) where (ρ0) is constant. A is the cross-sectional area of the wire. the resistance of the wire would be
A) [(ρ0)(L)]/A
B) (ρ0)/(2A)
C) [(ρ0)(L)]/(2A)
D) [2(ρ0)(L^2)]/A
E) [(ρ0)(L^2)]/(2A)


Homework Equations


r=(ρL)/A



The Attempt at a Solution


r=[(ρ0)(L^2)]/A

Am I missing something?
 
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Jay9313 said:

Homework Statement



A conducting wire has a resistivity, ρ as a function of its length, L, given by ρ=(ρ0)(L) where (ρ0) is constant. A is the cross-sectional area of the wire. the resistance of the wire would be
A) [(ρ0)(L)]/A
B) (ρ0)/(2A)
C) [(ρ0)(L)]/(2A)
D) [2(ρ0)(L^2)]/A
E) [(ρ0)(L^2)]/(2A)

Homework Equations


r=(ρL)/A

The Attempt at a Solution


r=[(ρ0)(L^2)]/A

Am I missing something?
Yes.

For a (very short) length, ΔL, of wire, the resistance, ΔR is given by, [itex]\displaystyle \Delta R=\rho\frac{\Delta L}{A}=\left(\rho_0 \cdot L\right)\frac{\Delta L}{A}\,.[/itex]
 

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