A couple of problems on motion and force

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SUMMARY

The discussion focuses on calculating the maximum deceleration rate for a truck carrying a 3200-kg crate, given a coefficient of static friction of 0.65. The normal force (N) is calculated as 31360 N, leading to a maximum frictional force of 20384 N. To determine the maximum deceleration, participants are advised to apply Newton's second law (F = ma) and the relationship between frictional force and mass. The key takeaway is that the deceleration must not exceed the frictional force divided by the mass of the crate to prevent it from sliding forward.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Ability to calculate normal force and frictional force
  • Familiarity with basic physics equations, particularly F = ma
NEXT STEPS
  • Study the application of Newton's second law in real-world scenarios
  • Learn about the dynamics of friction and its role in motion
  • Explore advanced topics in kinematics related to deceleration and stopping distances
  • Investigate the effects of different coefficients of friction on vehicle safety
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion and force, particularly in the context of vehicle dynamics and safety.

Gauss177
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Homework Statement



A flatbed truck is carrying a 3200-kg crate of heavy machinery. If the coefficient of static friction between the create and the bed of the truck is 0.65, what is the maximum rate at which the driver can decelerate when coming to a stop in order to avoid crushing the cab with the crate?

Homework Equations



fric = u*N
Fnet = m * a

The Attempt at a Solution



N = 3200*9.8 = 31360
fric = 0.65 * 31360 = 20384 N

thats as far as I got
 
Last edited:
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thechuckisback said:
fricc= u*N*d*e I think

What are d and e? The frictional force is equal to the coefficient of friction, mu, times the normal force which is usually denoted by N.
 
For 1), use Newton's 2nd law, F = ma. F is the decelerating force and the same force F acts on both the truck and the crate. But the actual force that slows down the crate is the force of friction between the crate and the floor of the truck. So what is the maximum frictional force you can have ?

2) is similar. Use F = ma and Fr = μm to get a. And minimum stopping distance comes from maximum decelerating (frictional) force.
 

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