A couple question on illumination.

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Homework Help Overview

The discussion revolves around problems related to illumination and the relationship between luminous intensity and distance from a light source. Participants are exploring how to apply formulas related to light intensity and distance to find unknown values in two specific scenarios involving lamps and their effects on illumination.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of formulas for illumination, questioning how to incorporate distance into their calculations. They explore the inverse square law of illumination and its application to the given problems.

Discussion Status

Some participants have provided guidance on using the relationship between intensity and distance, suggesting a formula to relate the two problems. There is acknowledgment of slight discrepancies between participant answers and those provided by an instructor, prompting requests for clarification.

Contextual Notes

Participants note the absence of distance variables in certain equations, which raises questions about how to approach the problems effectively. The discussion reflects a mix of attempts to validate their answers against instructor feedback.

jefgreen
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Q1:

Two lamps illuminate a screen equally. The first lamp has an intensity of 12.5cd and is 3.0m from the screen. The second lamp is 9.0m from the screen. What is its intensity?

I know I need to use P=4*pi*(I), but there is no variable included for distance (d). Another formula given is: Eill=P/(4*pi*d^2). How should I go about solving this problem now?
----------------------------------------------------------------------------------------------
Q2:

A 15cd point source lamp provide equal illuminations on a wall. if the 45cd lamp is 12m away from the wall, how far from the wall is the 15cd lamp.

Again, there is no variable for distance in the equation: P=4*pi*I.
 
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Illumination on a screen is inversely proportional to the square of the distance and directly proportional to the luminous intensity of the lamp.
So L1/d1^2 = L2/d2^2.
You can use this relation both the problems.
 
...
 
Last edited:
Instructor's answers:
#1: 110 cd
#2: 6.9 m
------------------------
My answers and work:
#1:

12.5 cd xxxxxx cd
-------- = --------
3.0m^2 9.0m^2

My answer: 112.5cd OR 113.0 cd.
---------------------------------------------------
My answers and work:
#2:

45 cd 15 cd
------ = ------
12 m xxxx m

My Answer: 4.00 m
---------------------------------------------------

As you can see, I'm just slightly off from what my instructor's answers were.

So, are my answers correct?
 
Bump. Am I correct?
 
Bump. All I need is clarification...
 
First answer is correct.
In the second problem
45/12^2 = 15/d^2.
Solve for d.
 
rl.bhat said:
First answer is correct.
In the second problem
45/12^2 = 15/d^2.
Solve for d.

Thank you, sir. :cool:
 

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