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hi,

i have been studying for GRE subject

and i saw this question but i could not solve it

the answer is 3/4

but i want to know how? , i guess it should be solved by double integral.

thanks in advance for any help

but i could not figure out how the area above the curve x=yz represents that probability geometrically ?

i have been studying for GRE subject

and i saw this question but i could not solve it

*x , y and z are selected independently and at random from the interval [0,1], then the probability that x is bigger than y*z is ?*the answer is 3/4

but i want to know how? , i guess it should be solved by double integral.

thanks in advance for any help

**i just figured out that [itex] \int_{0}^{1} \int_{0}^{1} (1-yz) dy dz = 3/4 [/itex]****edit:**but i could not figure out how the area above the curve x=yz represents that probability geometrically ?

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