A fixed string in the third harmonic

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Using:

[tex]v(x,t) = A_S_W \omega sin(\frac{\pi }{2}) cos(0)[/tex]

gives me: 5.33

then

[tex]a(x,t) = A_S_W \omega ^2 sin(\frac{\pi }{2}) sin(\frac{\pi }{2})[/tex]

gives me: 7700

Both of which are right. I disagree with mastering physics - if you diffentiate cos, it gives you minus sin:

[tex]a(x,t) = -A_S_W \omega ^2 sin(\frac{\pi }{2}) sin(\frac{\pi }{2})[/tex] giving -7700, which it said was wrong?

Many Thanks,

TFM
 
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Indeed you do get minus sin, but -7700 would be the maximum deceleration, and it asks for the maximum acceleration. At least that's what I tell myself.

Thanks for your help with the period, I think I was having a mental bock.
 
Have you got the right answer yet for the time, as I have left the thread marked unsolved until you have finished.:smile:

I think I was having a mental bock.

Don't worry, I think it happens to all of us from time to time!

TFM
 
Yeah, I got in the end. Thanks for that :smile:.

By the way are you still working on the 'instantaneous power in a standing wave' problem? Sketching the graphs is quite tricky.