A function that doesn't have a max/min in general, but does when restricted

  • #1
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1
Hello, I'm trying to construct a function f from R^2 -> R where f is everywhere differentiable, doesn't have a local min at 0 but if I restrict the domain of f to any line through the origin, 0 will be a (strict) min at that point..
I've been fooling around with this, but I don't really have any good strategies for figuring out how to make this function. Any tips? thank you
 
  • #2
Hmmm...

Intuitively, I think something like this could work:

[tex]f(x,y)=\left\{\begin{array}{cc} -e^{1/x^2} &\text{if}~y=x^2\\ 0 &\text{otherwise}\end{array}\right.[/tex]

This isn't continuous everywhere. But I do think that it is differentiable in 0 (because the function [itex]e^{1/x^2}[/itex] is part of a bump function.

Now I guess we should just smooth the function up. I have a feeling it might work.

I'll think of a better example.
 

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