A hard question from the Oxford interview

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SUMMARY

The discussion focuses on a physics problem involving two disks, where a small disk moves under gravity while a larger disk remains fixed. The key concepts include the conservation of energy and circular motion equations. The centripetal force required for the small disk's motion is derived from gravitational force components. The analysis concludes that the small disk will no longer touch the big disk when its centripetal acceleration exceeds the gravitational component acting towards the center of the larger disk.

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  • Understanding of conservation of energy principles
  • Familiarity with circular motion equations
  • Knowledge of centripetal force calculations
  • Basic concepts of gravitational force components
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  • Study the principles of conservation of mechanical energy in physics
  • Learn how to derive centripetal acceleration formulas
  • Explore the relationship between gravitational force and circular motion
  • Investigate real-world applications of centripetal force in engineering
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Students in physics, educators teaching mechanics, and anyone interested in solving complex motion problems involving forces and energy conservation.

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Homework Statement


See the attached picture.
The big disk is fixed on the ground, and the small disk move under the gravity. There is no friction between two disks. When will the small disk is no longer touch the big disk? Just measure the distance between the center of the small disk and the ground.


Homework Equations


The conservation of the energy
The equation of the circular motion


The Attempt at a Solution


I just consider that the centripetal force on the small disk, which is one of the component of the gravity on the small disk, may be the key to answer this question. But I really don't know how to write it into an equation and to solve it
 

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For a given velocity v, you can calculate the centripetal force required to keep the disk sliding. Gravity has to provide this force (but pay attention to its direction).
 
Since there is no rolling the potential energy is just converted into kinetic energy. The speed will be tangential to the line connecting it to centre of the big disc. One can simplify it by considering a point mass at 3r following a circular path. The component of g along the line to the centre of the big disc provides the centripetal acceleration.
 

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