MHB A line passing through two points

  • Thread starter Thread starter Guest2
  • Start date Start date
  • Tags Tags
    Line Points
AI Thread Summary
To find the value of \( a \) for the point \( (a, 4, -3) \) on the line through points \( p = (1,2,-1) \) and \( q = (3,1,0) \), the correct calculation shows that \( a = -3 \). The line can be expressed parametrically as \( (x,y,z) = (1,2,-1) + t(2,-1,1) \). By solving the equations derived from the line's parameters, it is confirmed that \( t = -2 \) leads to \( a = -3 \). However, the initial methodology had inaccuracies, particularly regarding the relationship between the line and the plane generated by points \( p \) and \( q \). The final conclusion is that \( a = -3 \) is indeed correct.
Guest2
Messages
192
Reaction score
0
If the line passing through the points $p = (1,2,-1)$ and $q = (3,1,0)$ contains the point $(a, 4,-3)$ then what's the value of $a$?

I think $a = -3$. but I'm not sure.

$(1,2,-1)x+(3,1,0)y = (a,4,-3)$

$(x,2x,-x)+(3y,y,0) = (a,4,-3)$

$(x+3y, 2x+y, -x) = (a, 4,-3)$

so $x = -3$, $y = -2$ and $a = -3$
 
Mathematics news on Phys.org
Your answer is correct, although the methodology is not as good as you might hope.

Firstly, you have a typo, it should be $x = 3$.

Secondly, although the line going through $p$ and $q$ does lie in the plane generated by $p$ and $q$, it is not true that any point in the plane so generated lies on that line. So you kind of got lucky.

The line through $p$ and $q$ is:

$\{(x,y,z) \in \Bbb R^3: (x,y,z) = p + t(q-p), t \in \Bbb R\}$.

We have:

$q - p = (2,-1,1)$, so our line is:

$(1,2,-1) + t(2,-1,1)$

so: $(2t+1,2-t,t-1) = (a,4,-3)$

Either $2-t = 4$ or $t-1 = -3$ leads to $t = -2$, and consequently $a = 2t + 1 = 2(-2) + 1 = -4 + 1 = -3$.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top