A Man and His Shadow: Velocity and Relationship with Sunlight

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SUMMARY

The discussion focuses on the relationship between a man's velocity and the velocity of his shadow under two conditions: indoors with a candle and outdoors under sunlight. The formula derived for the shadow's velocity is vshadow = (H / (H - h)) * v1 when the man is indoors. When outdoors, the shadow's velocity equals the man's velocity, vshadow = vman, due to the height difference being negligible (H >> h). Participants confirm the correctness of the solution and clarify misconceptions about shadow acceleration.

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Gyroscope

Homework Statement


One man, with height h, is inside a room. On the ceiling of the room there is a candle that is at a height H from the floor. The man moves in a straight line with velocity v1, passing below the candle.

a) Determine the velocity of the shadow of his head projected on the floor.

b) What is the relationship between the velocity of the man and the velocity of the shadow of his head when he walks outside below the sun.

Homework Equations


The Attempt at a Solution



a)

v_{\rm shadow}=\left \frac{H}{H-h} \right v_1

b)

In this case, H >> h, so vshadow=vman.

Am I right? Thanks in advance for your replies.
 
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I don't think you can use a scalar here. My experience is that a shadow "accelerates". When he is underneath the candle, there will be practically no shadow. When he is farther away, the shadow will be much larger. So it accelerates, so to speak.

Dorothy
 
Dorothy, but we are concerned only about the shadow of his head as we can see it as a point. Why do you say it is accelerating?
 
Hi Gyroscope,

Yes, sorry. I think your solution is correct.

Dorothy
 
No problem :biggrin: ... Thanks for replying to my post.
 
It is not that I don't trust Dorothy, but I would like a second opinion. I just love second opinions!
 

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