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A man walks on a straight road from his home to market 2.5km

  1. May 30, 2012 #1
    1. The problem statement, all variables and given/known data
    A man walks on a straight road from his home to market 2.5km away with a speed of 5km/h. Finding the market closed, he instantly turns and walk back home with a speed of 7.5km/h.
    For the given time intervals (i) 0 to 30minutes. (ii) 0 to 50minutes., (iii) 0 to40 min. What is the
    a) magnitude of average velocity and
    b) average speed of the man.


    2. Relevant equations



    3. The attempt at a solution
    distance=displacement
    d=s*t
    2.5=5*x
    x=5/2.5=2
     
  2. jcsd
  3. May 30, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
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    welcome to pf!

    hi reshmi! welcome to pf! :smile:

    you're obviously not understanding the question, so let's rewrite it …

    A man walks on a straight road from his home to market 2.5km away with a speed of 5km/h. So it takes him 30 minutes.

    Finding the market closed, he instantly turns and walk back home with a speed of 7.5km/h. So that takes him 20 minutes, making a total of 50 minutes.

    For the given time intervals (i) 0 to 30minutes. (ii) 0 to 50minutes., (iii) 0 to40 min. What is the
    a) magnitude of total displacement over total time
    b) average speed of the man.​

    :wink:
     
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