# A man walks on a straight road from his home to market 2.5km

## Homework Statement

A man walks on a straight road from his home to market 2.5km away with a speed of 5km/h. Finding the market closed, he instantly turns and walk back home with a speed of 7.5km/h.
For the given time intervals (i) 0 to 30minutes. (ii) 0 to 50minutes., (iii) 0 to40 min. What is the
a) magnitude of average velocity and
b) average speed of the man.

## The Attempt at a Solution

distance=displacement
d=s*t
2.5=5*x
x=5/2.5=2

tiny-tim
Homework Helper
welcome to pf!

hi reshmi! welcome to pf!

you're obviously not understanding the question, so let's rewrite it …

A man walks on a straight road from his home to market 2.5km away with a speed of 5km/h. So it takes him 30 minutes.

Finding the market closed, he instantly turns and walk back home with a speed of 7.5km/h. So that takes him 20 minutes, making a total of 50 minutes.

For the given time intervals (i) 0 to 30minutes. (ii) 0 to 50minutes., (iii) 0 to40 min. What is the
a) magnitude of total displacement over total time
b) average speed of the man.​