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A mass oscillating at the end of a spring

  1. Apr 21, 2015 #1
    1. A 250-g object hangs from a spring and oscillates with an amplitude of 5.42 cm. The spring constant is 4.80 N/m.
    a) What is the acceleration of the object when the displacement is 4.27 cm [down]?

    I put:
    m=0.25 kg
    d=0.0542 m
    k=48 N/m
    x=0.0427m
    Therefore:
    F=kx which leads to a=kx/m
    a=(48 N/m)(0.0427 m)/0.25 kg
    a=8.10 m/s^2 [up]
    b) What is the maximum speed of the object?
    I put:
    m=0.25 kg
    d=0.0542 m
    k=48 N/m
    x=0.0427m
    a=8.10 m/s^2 [up] (I think)
    Not sure which equation to use...
    c) At what position will the maximum speed occur?
    I'd need B to know this, please help me out.
    Thanks in advance!
     
  2. jcsd
  3. Apr 21, 2015 #2

    berkeman

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    Staff: Mentor

    It looks like you have a typo there -- can you re-check the problem statement? :smile:
     
  4. Apr 21, 2015 #3
    i'm sorry, what is my typo?
     
  5. Apr 21, 2015 #4

    berkeman

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    Staff: Mentor

    :smile:
     
  6. Apr 21, 2015 #5

    haruspex

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    There is another error in the OP solution to a).
    In the equation F=ma, F is the net of all forces in the direction of the acceleration. What are all the forces acting on the mass?
     
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