1. A 250-g object hangs from a spring and oscillates with an amplitude of 5.42 cm. The spring constant is 4.80 N/m. a) What is the acceleration of the object when the displacement is 4.27 cm [down]? I put: m=0.25 kg d=0.0542 m k=48 N/m x=0.0427m Therefore: F=kx which leads to a=kx/m a=(48 N/m)(0.0427 m)/0.25 kg a=8.10 m/s^2 [up] b) What is the maximum speed of the object? I put: m=0.25 kg d=0.0542 m k=48 N/m x=0.0427m a=8.10 m/s^2 [up] (I think) Not sure which equation to use... c) At what position will the maximum speed occur? I'd need B to know this, please help me out. Thanks in advance!