A mass oscillating at the end of a spring

  • #1
1. A 250-g object hangs from a spring and oscillates with an amplitude of 5.42 cm. The spring constant is 4.80 N/m.
a) What is the acceleration of the object when the displacement is 4.27 cm [down]?

I put:
m=0.25 kg
d=0.0542 m
k=48 N/m
x=0.0427m
Therefore:
F=kx which leads to a=kx/m
a=(48 N/m)(0.0427 m)/0.25 kg
a=8.10 m/s^2 [up]
b) What is the maximum speed of the object?
I put:
m=0.25 kg
d=0.0542 m
k=48 N/m
x=0.0427m
a=8.10 m/s^2 [up] (I think)
Not sure which equation to use...
c) At what position will the maximum speed occur?
I'd need B to know this, please help me out.
Thanks in advance!
 

Answers and Replies

  • #2
berkeman
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k=48 N/m
It looks like you have a typo there -- can you re-check the problem statement? :smile:
 
  • #3
It looks like you have a typo there -- can you re-check the problem statement? :smile:
i'm sorry, what is my typo?
 
  • #5
haruspex
Science Advisor
Homework Helper
Insights Author
Gold Member
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5,877
There is another error in the OP solution to a).
In the equation F=ma, F is the net of all forces in the direction of the acceleration. What are all the forces acting on the mass?
 

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