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**1. A 250-g object hangs from a spring and oscillates with an amplitude of 5.42 cm. The spring constant is 4.80 N/m.**

a) What is the acceleration of the object when the displacement is 4.27 cm [down]?

a) What is the acceleration of the object when the displacement is 4.27 cm [down]?

I put:

m=0.25 kg

d=0.0542 m

k=48 N/m

x=0.0427m

Therefore:

F=kx which leads to a=kx/m

a=(48 N/m)(0.0427 m)/0.25 kg

a=8.10 m/s^2 [up]

**b) What is the maximum speed of the object?**

I put:

m=0.25 kg

d=0.0542 m

k=48 N/m

x=0.0427m

a=8.10 m/s^2 [up] (I think)

Not sure which equation to use...

**c) At what position will the maximum speed occur?**

I'd need

**B**to know this, please help me out.

Thanks in advance!