ZaidAlyafey said:
Sudharaka said:Hi Zaid, :)
Both of your links refer to the same page. :)
topsquark said:
Good point. Not to hijack the thread but can you quickly tell me how you would tell Wolfram x is real?Random Variable said:You have to somehow tell Wolfram Alpha that $x$ is a real variable. Otherwise it will assume that $x$ is a complex variable. And if $x$ is a complex variable, $\displaystyle \int \frac{1}{x} \ dz = \log(x) + C$ is a true statement.
Yeah, right. An awful lot of mistakes. I once tried that send message and sent the error and correction but no one looked at it, and remains incorrect today as well, and so I think its useless. In fact, I think Wikipedia is less error-prone than Mathworld.mathbalarka said:I often come up with a whole lot of mistakes on that particular site.
Look at the leftmost edge of the page and you'll see a tool to send message to the editorial board. Quote the line you feel is incorrect, then send them that.
Sawarnik said:Yeah, right. An awful lot of mistakes. I once tried that send message and sent the error and correction but no one looked at it, and remains incorrect today as well, and so I think its useless. In fact, I think Wikipedia is less error-prone than Mathworld.
I like Serena said:Which mistake?
Sawarnik said:One that I found recently: Semiperimeter -- from Wolfram MathWorld
I like Serena said:So where is the mistake in that article?
Sawarnik said:"and Brahmagupta's formula for the area of a quadrilateral:"
Is that formula after that Brahmagupta's!
Pranav said:
Sawarnik said:
IlikeSerena said:Hmm, so the math is perfectly correct and as such MathWorld is reliable.
mathbalarka said:At least, more than wikipedia in any case.
Where is the mistake in wikipedia?
I like Serena said:Hmm, so the math is perfectly correct and as such MathWorld is reliable.
The problem is that the credits given are not correct in that article.
Just now, I have sent a contribution to MathWorld with the suggestion to correct this.
We'll see.
mathbalarka said:At least, more than wikipedia in any case.