POTW A Nonlinear Elliptic PDE on a Bounded Domain

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In the discussion on a nonlinear elliptic PDE, the focus is on proving the non-existence of a C^2-solution u for the equation Δu^2 = f in a smooth, bounded domain D, with boundary condition u = 0 on ∂D. A clarification is sought regarding the meaning of u = 0 on the boundary, emphasizing that if u is in C^2(D) ∩ C(∂D), the conclusion can be derived directly from the maximum principle. The smoothness of the boundary ∂D is deemed unnecessary for this assertion. The conversation highlights the importance of understanding boundary conditions in the context of elliptic PDEs. Overall, the discussion underscores the complexities involved in nonlinear elliptic problems and their solutions.
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Let ##D## be a smooth, bounded domain in ##\mathbb{R}^n## and ##f : D \to (0, \infty)## a continuous function. Prove that there exists no ##C^2##-solution ##u## of the nonlinear elliptic problem ##\Delta u^2 = f## in ##D##, ##u = 0## on ##\partial D##.
 
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Start with Green's identity ##\int_D \left(\psi \Delta \psi +||\nabla\psi||^2\right) dV=\int_{\partial D}\psi\nabla\psi\cdot dS.##

Substituting ##\psi=u^2,## we see that the lefthand side is strictly positive, but the righthand side would be zero if ##u=0## on the boundary.
 
Just adding a comment @Infrared's solution.

Since the two terms in the integrand on the left-hand side is nonnegative, if its integral over ##D## is zero, then both those terms are zero in ##D##. In particular ##fu^2 = 0## in ##D##, forcing ##u = 0## (since ##f## is positive). We get ##f = \Delta u^2 = 0##, a contradiction. Therefore, the integral on the left-hand side is strictly positive.
 
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it is not clear enough what ##u=0## on ##\partial D## means. If ##u\in C^2(D)\cap C(\overline D)## then the assertion follows from the maximum principle directly; smoothness of ##\partial D## is not needed
 

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