A number Theory Question: Solve 2^x=3^y+509 over positive integers

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SUMMARY

The equation \(2^x = 3^y + 509\) has been conclusively solved for positive integers, yielding the unique solution \((x, y) = (9, 1)\). The analysis shows that for any \(x > 9\) and \(y > 1\), no additional solutions exist. The reasoning involves manipulating the equation into the form \(2^9(2^{x-9} - 1) = 3(3^{y-1} - 1)\) and demonstrating that the constraints imposed by the prime factors of 3 and 509 limit the possibilities for \(a\) and \(b\) to non-positive integers.

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Homework Statement
Question about number theory
Relevant Equations
Solve ##2^x=3^y+509## over positive integers.
My attempt and solution :
$$2^x=3^y+509\Longrightarrow 2^x-512=3^y+509-512\Longrightarrow 2^x-2^9=3^y-3$$
$$\Longrightarrow 2^9(2^{x-9}-1)=3(3^{y-1}-1)$$
$$\Longrightarrow (x,~y)=\boxed{(9,~1)}$$
İs there any solution?
 
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İf $$x>9$$ and $$y>1$$ then another solution let $$a,b\in\mathbb{Z^+}$$ $$(9+a,1+b)$$. Because of ##2^{a+9}=3^{b+1}+509## and ##2^9=3+509## $$2^a(3+509)=509+3^{b+1}$$ $$(2^a-1)509=3(3^b-2^a)$$ But 3 and 509 numbers prime so $$2^a-1=3$$ and $$3^b-2^a=509$$ . But in that case $$3^b=513$$ so b not be a positive number. Hence only solution is ##(9,1)##
 

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