# A particle in 1D potential well

1. Dec 11, 2013

### White_M

Hello,

What does it means when a particle having mass "m" in a one dimentional potential well has the potential given by:
V(x)=
$\stackrel{-\alpha δ(x) for |x|<a}{∞ for |x|≥a}$

where δ(x) is the delta function and $\alpha$ is a constant.

I understand that the well boundries have infinite potential but what about the well? Does it have -$\alpha$ potential only for x=0? What is the potential for |X|<a and x≠0? And how do I write the boundry conditions here?

10x!
Y.

2. Dec 11, 2013

### ChrisVer

the potential in for X>a or X<-a is infinite
the potential on point X=0 is -infinite due to the delta function (but its integral for example is not).
the rest |X|<a and not 0, the potential is zero.

The boundary conditions on +/-a are the same (your wavefunction must vanish).
http://en.wikipedia.org/wiki/Delta_potential