A particle is moving along the x-axis subject to the potential energy function

Click For Summary
To determine the x-component of the net force on a particle moving along the x-axis with the potential energy function U(x) = 1/x + x² + x - 1 at x = 3.67 m, the relationship between force and potential energy must be utilized. The net force can be found using the equation F(x) = -dU/dx, which requires calculating the derivative of the potential energy function. Attempts to integrate the potential energy function or directly substitute the position into the equation did not yield the correct force. Clarification on how to derive the force from the potential energy function is needed for a proper solution. Understanding the correct application of the derivative is essential for solving the problem.
AD_3
Messages
6
Reaction score
0

Homework Statement



A particle is moving along the x-axis subject to the potential energy function U(x) = 1/ x + x2 + x – 1. Determine the x-component of the net force on the particle at the coordinate x = 3.67 m.

Homework Equations


delta U=-∫F(x)*dx

The Attempt at a Solution


I tried to take the integral of the given function from 0 to 3.67 but that didn't work and I tried plugging in the the distance into the equation and that didn't work either.
 
Physics news on Phys.org
You need the force. How do you get force from potential?


ehild
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
1K