A particle is moving with a velocity of 60.0 m/s

[r-soy]

A particle is moving with a velocity of 60.0 m/s in positive x direction at t= 0 and t = 15.0 s the velcity decreases uniformly to zero . What was the acceleration during this 15.0-s interval ? what is the significance of the sign of your answer ?





my answer is



Vo = 0

a = 60 - 0 / 15 = 4

 

[tiny-tim]

Hi r-soy!

You must get into the habit of writing the formula clearly on one line, then filling in the numbers on the next line …

if you'd done that, you wouldn't have got the wrong answer!

So try again, and start with the full formula. ​