(adsbygoogle = window.adsbygoogle || []).push({}); Question:

Coherent light with wavelength 400 nm passes through two very narrow slits that are separated by 0.200 mm and the interference pattern is observed on a screen 4.00 m from the slits.

A

What is the width (in mm) of the central interference maximum?

[tex]y_m = R \cdot \frac{m \cdot \lambda}{d}[/tex]

I thought I would get the width of the central interference maximum by doubling [tex]y_m = 4.00 \cdot \frac{4.00 \cdot 1 \cdot 4.00 \cdot 10^(-9)}{.00200} = .016[/tex].

That's not correct, though.

Why was my approach incorrect?

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# Homework Help: A problem using Young's equation from the double-slit experiment

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