Double-Slit Experiment problem?

In summary, the third order bright fringe in a double-slit experiment is 15 mm from the central fringe. To find the distance of the first (zero-th order) dark fringe from the central maximum, you can use the equation dsinθ = nλ, where d is the distance between the two slits, θ is the angle, and n is the order of the fringe. However, for small angles, you can use the approximation sinθ = θ = x / D, where x is the fringe displacement from the central maximum and D is the distance to the screen.
  • #1
brinstar
62
1

Homework Statement


In a double-slit experiment, the third order bright fringe is 15 mm from the central fringe. What is the distance of the first (zero-th order) dark fringe from the central maximum?

Homework Equations


(m+.5)(lambda) = dsin(theta) => dark fringe
m(lambda) = dsin(theta) => bright fringe

The Attempt at a Solution


I honestly don't know. Like, there's no angle or wavelength. The most I've come up with is 15 mm divided by 3 (because it's the third) and getting 5 mm. I seriously don't know.
 
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  • #2
the equation you need is
dsinθ = nλ for maxima...you have this in your post
 
  • #3
lychette said:
the equation you need is
dsinθ = nλ for maxima...you have this in your post

But where do I get the angle and wavelength from?
 
  • #4
For angles this small you can use the approximation: sin theta = theta = x / D where x
is the fringe displacement from the central maximum and D is the distance to the screen.
 

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