1. Two 40g (.04kg) projectiles are launched horizontally at a point 2m above the ground. One lands 200m away and the other lands 250m. Find the PE and the KE of each projectile at launch. 2. dx= vx dy=Vy(t)+1/2gt^2(t) KE= 1/2mv^2 PE=mgh 3.I tried plugging the variables into a drop equation, and came up with vi=0, no final velocity, d=200, t=6.4, and a= -9.8 The variable I solved for was time. I'd like to know if I'm on the correct track, or if I'm doing this horribly, horribly wrong.