The discussion focuses on deriving expressions related to the motion of a block pushed against a spring and subsequently released, leading to projectile motion. Key equations include the conservation of energy, represented as \( mgh + \frac{1}{2}kx^2 = \frac{1}{2}mv_f^2 \), and the relationship for spring constant \( k = m\frac{D^2}{x^2} \frac{g}{2h} \). Participants clarify the use of kinematic relationships and the implications of constant versus varying acceleration in the horizontal direction. The final expressions derived are essential for understanding the dynamics of the system.
PREREQUISITESStudents in physics, engineers working with mechanical systems, and anyone interested in the principles of energy conservation and projectile motion dynamics.
Yes, while the block is in parabolic motion the horizontal velocity remains constant throughout its path. I think I understood! Thank you.haruspex said:Why "but"?
Yes, for part b we only need to consider motion after the block leaves the table, and in that phase vertical acceleration is constant, g, and horizontal acceleration is constant, 0. So we can apply the kinematic equations for constant acceleration.