Can You Solve the $$\sqrt {car}=37$$ Puzzle?

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SUMMARY

The discussion revolves around the mathematical puzzle $$\sqrt {car}=37$$, where participants explore the implications of this equation. The key insight is that if $$c = 1369$$, then $$\sqrt {car}$$ holds true under specific conditions. Additional hints provided include $$\sqrt {cdo}=38$$, $$\sqrt{cpw}=42$$, and $$\sqrt{doj}=49$$, suggesting a consistent system of relationships among these variables. The excitement stems from the personal connection to the number 37, which is a prime number and a favorite of one participant.

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TL;DR
My daughter discovered this using an unusual program I wrote for her.
There is a precise sense in which it is correct to say: $$\sqrt {car}=37$$

The puzzle is to figure out in what sense this is true.

[What made this so exciting for her is that 37 is her favorite number, and that she was obsessed with car models at the time].
 
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37 is prime.

but we could have c = 1369
and if a NE r, ( ie if a = r = 1 ), then they can be just the reciprocal of one another.

( I would like the large bunny in the corner for my girlfriend. )
 
The solution I'm looking for is much more natural than that. I'll give a big hint: $$\sqrt {cdo}=38$$ and $$\sqrt{cpw}=42$$ All 3 square roots have to be true under the same system. One more, just for fun: $$\sqrt{doj}=49$$
 
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Base 26 comes to mind ...
 
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Filip Larsen said:
Base 26 comes to mind ...
Winner!
 
I think I have solved it. How do I create a "spoiler"?
 
Buzz Bloom said:
I think I have solved it. How do I create a "spoiler"?
In edit message window, touch the arrow next to the 3 dots. Spoiler is one of the options.
 
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The three letters "c", "a", and "r" each have a different value between 1 and 26 inclusive.
The notation represents a three digit (base 26) number. That is c has a coefficient of 262, a has a coefficient of 26, and r has a coefficient of 1. This produces the equation below.
676 c + 26 a + r = 372 = 1369​
c = 1 because c>1 implies 676 c > 1369.
Therefore,
26 a + r = 693.​
Now
693/26 = 26.65...​
Therefore, a = 26, and r = 693 - 676 = 17.

The cdo problem is also solved the same way, although c now has a different value.
c = 2, 26 d + o = 382 = 1444 - 1352 = 92
Now
92/26 = 3.5...​
Therefore d = 3 and o = 14.

Oops. I now see that I made a mistake. I will correct it in a separate post.
 
Last edited:
Base on the the cdo solution
c = 2
d = 3
o = 14
in the previous post, I now see that in the car problem
c = 2
a = 1
r = 17.

The general pattern is
each letter has the value of its position in the alphabet - 1.
 
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Buzz Bloom said:
Base on the the cdo solution
c = 2
d = 3
o = 14
in the previous post, I now see that in the car problem
c = 2
a = 1
r = 17.

The general pattern is
each letter has the value of its position in the alphabet - 1.
Correct.
 

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