A question about surjective module-homomorphisms

  • Context: MHB 
  • Thread starter Thread starter steenis
  • Start date Start date
  • Tags Tags
    Surjective
Click For Summary
SUMMARY

This discussion centers on the properties of surjective $R$-homomorphisms between $R$-modules, specifically addressing the relationship between preimages of sums of submodules. The user establishes that for a surjective homomorphism $f: A \longrightarrow B$, the equality $f^{-1}(X) + f^{-1}(Y) = f^{-1}(X + Y)$ holds true for submodules $X$ and $Y$ of $B$. The proof is confirmed through the demonstration that $f^{-1}(X + Y) \subseteq f^{-1}(X) + f^{-1}(Y)$ and the reverse inclusion, thus establishing the equality definitively.

PREREQUISITES
  • Understanding of $R$-modules and their properties
  • Familiarity with homomorphisms, specifically $R$-homomorphisms
  • Knowledge of submodules and their operations
  • Basic concepts of surjectivity in the context of functions
NEXT STEPS
  • Study the properties of $R$-modules in detail, focusing on homomorphisms
  • Learn about the structure of submodules and their interactions
  • Explore the implications of surjectivity in module theory
  • Investigate references on module theory, particularly those covering homomorphism properties
USEFUL FOR

Mathematicians, algebraists, and students studying module theory, particularly those interested in the properties of homomorphisms and submodules in algebraic structures.

steenis
Messages
312
Reaction score
18
I have the following question about surjective module-homomorphisms.

Let $f:A \longrightarrow B$ be a surjective $R$-homomorphism between $R$-modules $A$ and $B$.
Let $S, T$ be submodules of $A$ and let $X, Y$ be submodules of $B$.

I can prove that in general
$$f(S+T)=f(S)+f(T)$$
and in general
$$f^{-1}(X)+ f^{-1}(Y) \subseteq f^{-1}(X+Y)$$
If $f$ is surjective we can combine these two, and we have
$$f(f^{-1}(X)+ f^{-1}(Y))=f f^{-1}(X)+f f^{-1}(Y)=X+Y$$
But I need this:
$$f^{-1}(X)+ f^{-1}(Y)=f^{-1}(X+Y)$$
given that $f$ is surjective.

I cannot find the proof and I do not know if it is true, can somebody help me to prove this or give a counterexample or give a reference?
 
Physics news on Phys.org
steenis said:
I have the following question about surjective module-homomorphisms.

Let $f:A \longrightarrow B$ be a surjective $R$-homomorphism between $R$-modules $A$ and $B$.
Let $S, T$ be submodules of $A$ and let $X, Y$ be submodules of $B$.

I can prove that in general
$$f(S+T)=f(S)+f(T)$$
and in general
$$f^{-1}(X)+ f^{-1}(Y) \subseteq f^{-1}(X+Y)$$
If $f$ is surjective we can combine these two, and we have
$$f(f^{-1}(X)+ f^{-1}(Y))=f f^{-1}(X)+f f^{-1}(Y)=X+Y$$
But I need this:
$$f^{-1}(X)+ f^{-1}(Y)=f^{-1}(X+Y)$$
given that $f$ is surjective.

I cannot find the proof and I do not know if it is true, can somebody help me to prove this or give a counterexample or give a reference?
If $a\in f^{-1}(X+Y)$ then $f(a) = x+y$, for some $x$ in $X$ and $y$ in $Y$. If $f$ is surjective then $x = f(b)$ and $y = f(c)$, for some $b,c\in A$. If $d = a-b-c$ then $f(d) = f(a) - f(b) - f(c) = 0.$ It follows that $b+d \in f^{-1}(X)$, and then $a = (b+d) + c \in f^{-1}(X)+ f^{-1}(Y)$.

That shows that $ f^{-1}(X+Y) \subseteq f^{-1}(X)+ f^{-1}(Y)$. You have already shown the reverse inequality, so it follows that $ f^{-1}(X+Y) = f^{-1}(X)+ f^{-1}(Y)$.
 
Thank you very much, This is a great help !
 
Doe anyone know references (books or online) in which this kind of "fomulae" of modules (or groups or rings, ...) are listed and maybe proved ?
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 0 ·
Replies
0
Views
928
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 3 ·
Replies
3
Views
980
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K