A question about the Doppler efffect

  • Thread starter Thread starter taculator
  • Start date Start date
  • Tags Tags
    Doppler
Click For Summary
SUMMARY

The discussion centers on the Doppler effect as applied to a commuter train moving at 40 m/s while sounding a horn at a frequency of 320 Hz. The participants calculated the frequency change detected by a person on the platform, using the formula for frequency of the detector: Fd = (Vsound ± Vd) / (Vsound ± Vs) × Fs. The correct frequency shift was debated, with calculations yielding results around 75.7 Hz, while some participants obtained slightly different values due to variations in the speed of sound used (343 m/s vs. 340 m/s). The wavelength was determined using the formula λ = c / f, where c is the speed of sound.

PREREQUISITES
  • Understanding of the Doppler effect in sound waves
  • Familiarity with the formula for frequency shift in moving source and detector scenarios
  • Knowledge of basic wave properties, including frequency and wavelength
  • Ability to perform calculations involving the speed of sound (343 m/s)
NEXT STEPS
  • Study the derivation and application of the Doppler effect equations in various contexts
  • Learn about the impact of different mediums on the speed of sound
  • Explore advanced applications of the Doppler effect in astrophysics and radar technology
  • Investigate the relationship between frequency, wavelength, and speed of sound in different scenarios
USEFUL FOR

Students studying physics, educators teaching wave mechanics, and anyone interested in understanding sound wave behavior in moving systems.

taculator
Messages
7
Reaction score
0

Homework Statement



A commuter train passes a passenger platform at a constant speed of 40 m/s. The train horn is sounded at its characteristic frequency of 320 hz. A) What change in frequency is detected by a person on the platform as the train passes? B) What wavelength is detected by a person on the platform as the train approaches?

Homework Equations


Frequency of detector = (Velocity of Sound+/- Velocity of Detector)/(Velocity of Sound +/- Velocity of Source) times Frequency of Source


The Attempt at a Solution



since the source (train) is moving towards the detector( person on platform) intially i did
Fd= (Vsound)/(Vsound+40) times Fs

where f is frequency
fd is 320 hz
and vsound is 343 m/s

I plugged in and i got that the frequency of the source was 282.7 hz, and then I plugged that into

Fd= (Vsound)/(Vsound-40) times Fs

because that would be the frequency of the detector as the train passes away.
After doing this I found that the change in frequency to be about 84 hz, whereas the answer key said: 75.7 Hz

I know how to solve part B because wavelength= velocity/ frequency but i don't have the correct frequency.


I wasn;t sure whether 320 hertz was the frequency of the detector or the source, so I plugged it into both to solve for the other, but I never ended up getting
 
Physics news on Phys.org
320 is the frequency of the source. Solving for the two frequencies and taking the difference using 340m/s for c I got a somewhat different answer than either yours or the key. Mine was slightly smaller than the keys.

Using the approximation that the shift delta F= -(Vel/c) x f where c= speed of sound.

I get very close to the key's answer. Wavelength is calculated using the formula c=f x lambda where f is the preceived frequency.
 
Ahh i see you used 320 for Fs.

The reason that you got a slightly different answer was because in my book velocity of sound is given as 343 m/s.

The reason I was confused originally is because in the problem it stated "characteristic frequency" so I automatically thought that to be the frequency of the detector, since that can change.

But thank you very much!
 
Your welcome. I took characteristic to mean that this was the horn's primary frequency. Usually they are made up of several frequencies but tht is completely beside the point.

BTW, I tried both 340 and 343 and couldn't get the keys answer for total frequency shift using the proper eqns, but who knows may have made a mistake. I believe the answer was in the 73-74 Hz range. Using the approximation I was able to get 75Hz.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 18 ·
Replies
18
Views
13K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K