A quick projectile motion problem. Please help me Thanks

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SUMMARY

The problem involves a marble thrown horizontally at a speed of 23.4 m/s from a building, striking the ground at an angle of 61.8° with the horizontal. The vertical acceleration is -9.8 m/s², and the initial vertical velocity (Voy) is 0 m/s. To determine the height from which the marble was thrown, one must use trigonometric functions, specifically the tangent function, to find the vertical velocity component and subsequently apply kinematic equations.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of trigonometric functions, particularly tangent
  • Familiarity with kinematic equations
  • Basic vector analysis in physics
NEXT STEPS
  • Study the derivation of kinematic equations for projectile motion
  • Learn how to apply trigonometric functions to resolve vector components
  • Explore the concept of velocity vectors in two dimensions
  • Practice solving similar projectile motion problems with varying angles and initial speeds
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Students in physics courses, educators teaching projectile motion, and anyone interested in applying mathematical concepts to real-world motion scenarios.

Miss1nik2
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A marble is thrown horizontally with a speed of 23.4 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 61.8 ° with the horizontal. From what height above the ground was the marble thrown?

So far I have found Ay= -9.8, Ax= 0, Vox=23.4, Voy=0. And Vx=23.4 (im not sure if I need that).

Any help will be greatly appreciated! Thank you!
 
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remember velocity is a vector too and can be treated like distances. Draw a triangle to represent the x and y velocities. if you set it up right you should be able to use the Tan funtion to find the y velocity component. I'm sure you can figure it out from there
 

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