1. The problem statement, all variables and given/known data A child sitting in a tree throws his apple core from where he is perched (a height of 4.0m) with a velocity of 5.0m/s [35 deg above horizontal] and it hits the ground right next to his friend. a)how long is it before the apple core hits the ground? b)how far from the base of the tree will the apple core land? c)what is the velocity of the apple core on impact? 2. Relevant equations suvat pythag. quad. form. 3. The attempt at a solution Given: Vi=5.0m/s [35 deg above horizontal] Δdy = 4.0m a) Find Δt. Let [down] and [forward] be positive. Initial Velocity Components: Vix = 5m/s (cos35) = 4.095760221m/s Viy = 5m/s (sin35) = -2.867882182m/s *Note: I threw the negative on the y-component because it is travelling upwards. Acceleration Components: ax = 0m/s/s ay = 9.8m/s/s Calculation for part A: Δdy = ViyΔt +1/2 (ay)Δt2 4.0m = -2.867882182m/s Δt + 4.9m/s/s (Δt2) In order to isolate the time variable, I rearranged to the form ax2+bx+c=0 and solved via the quadratic formula. The only real root yielded was x=1.242359580605109 Therefore, Δt = 1.242359580605109 seconds b) Find Δdx. Calculation for part B: Δdx = VixΔt +1/2 (ax)Δt2 Δdx = 4.095760221m/s (1.242359580605109 seconds) + 0 Δdx = 5.08840695042 m c) Find Vf Components of Vf: Vfx Vfx2 = Vix2+2axΔdx Since ax=0m/s/s, Vfx=Vix ∴ Vfx=5m/s Vfy Vfy2 = Viy2+2ayΔdy Vfy2 = 8.22474821m2/s2 + 78.4m2/s2 Vfy = √86.62474821 Vfy = 9.307241708m/s Vf = √(Vfx2 +Vfy2 Vf = √14.30724171 Vf = 3.782491469m/s Answers rounded: Δt = 1.24 seconds Δdx = 5.088 m Vf = 3.78 m/s I know the sig digits aren't correct but I didn't want to sacrifice accuracy. Are these answers correct?